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Help with Force and Gravity


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He needed to try and drop them from higher up...you won't see the difference over a height of only 2 metres...

 

if everything fell at the same rate then why do objects have different terminal velocities?

 

Terminal Velocity is expressed as Vt=sqrt (2mg over pACd)

 

Vt is the terminal velocity,

m is the mass of the falling object,

g is gravitational acceleration at the Earth's surface,

Cd is the drag coefficient,

ρ is the density of the fluid the object is falling through, and

A is the object's cross-sectional area.

 

This takes into account most of the factors affecting a falling object..

 

 

You mean that my education suffered because he was only a short house?

I bet they had taller science teachers at grammar schools!;)

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No,I'm sorry,it does work.Despite it being over 40 years ago I clearly remember our physics teacher "Rocker" Rodgers holding in outstreched arms a tennis ball and a cricket ball,letting them go at the same time and them both hitting the floor at the same time.It was like witnessing witchcraft!

Either the laws of physics have changed since then(decimalisation?) or there really was no atmosphere in Mr Rodgers physics lessons!

 

Repeat the experiment with a feather and a cricket ball then and you will see how important air resistance can be....

 

If you get an oil filled column and drop a glass marble and a steel ball bearing (of equal sizes) in you will find that the steel falls faster as well.

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Repeat the experiment with a feather and a cricket ball then and you will see how important air resistance can be....

If you get an oil filled column and drop a glass marble and a steel ball bearing (of equal sizes) in you will find that the steel falls faster as well.

 

Yes,I do remember him mentioning that aswell.But it doesn't make for such a remarkable demonsration,does it? I mean,everybody knows that a feather falls more slowly than a cricket ball.You're not going to win many Batman cards in the playground with that bet!

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