Halibut Posted September 13, 2013 Share Posted September 13, 2013 Consider the problem if there are lots of doors- say 100 (Total_Doors). There are 100 doors, behind 1 door is the prize, the remainder have goats. So pick a door. You have a 1 in 100 chance of picking the prize. That is; a very good chance of picking a goat:- remember you have probably got a goat. The host knows what's behind every door, The rules say a) if the chosen door contains the prize the host must open 98 doors (Total_Doors - 2 ) containing goats, leaving the chosen door and a goat door b) if the chosen door contains a goat the host must open 98 (Total_Doors - 2 ) doors containing goats, leaving the chosen (goat) door and the prize door You are now given the opportunity to stick or switch ( remember when you started off you have probably picked a goat ). So you switch, and there is a very good chance of winning the prize. The above rules apply for any number of doors, in the Monty Hall example the total number of doors is 3, so the host can only open 1 door. That's by far the best explanation I've ever come across - thankyou! Link to comment Share on other sites More sharing options...
Brentner Posted September 16, 2013 Share Posted September 16, 2013 Consider the problem if there are lots of doors- say 100 (Total_Doors). There are 100 doors, behind 1 door is the prize, the remainder have goats. So pick a door. You have a 1 in 100 chance of picking the prize. That is; a very good chance of picking a goat:- remember you have probably got a goat. The host knows what's behind every door, The rules say a) if the chosen door contains the prize the host must open 98 doors (Total_Doors - 2 ) containing goats, leaving the chosen door and a goat door b) if the chosen door contains a goat the host must open 98 (Total_Doors - 2 ) doors containing goats, leaving the chosen (goat) door and the prize door You are now given the opportunity to stick or switch ( remember when you started off you have probably picked a goat ). So you switch, and there is a very good chance of winning the prize. The above rules apply for any number of doors, in the Monty Hall example the total number of doors is 3, so the host can only open 1 door. Whoa... Thank you! A very good explanation indeed. Took me a while, but I get it now. Link to comment Share on other sites More sharing options...
Jeffrey Shaw Posted September 16, 2013 Share Posted September 16, 2013 I like this type of mindbender, even though I guessed wrong. But I'm puzzled by the counterposing of goats and cars. In what context are they ever plausible alternative choices? Link to comment Share on other sites More sharing options...
altus Posted September 16, 2013 Share Posted September 16, 2013 I like this type of mindbender, even though I guessed wrong. But I'm puzzled by the counterposing of goats and cars. In what context are they ever plausible alternative choices? They are not meant to be vaguely equivalent prizes. There's be no jeopardy in making the wrong choice if a contestant would be happy to win either prize. Link to comment Share on other sites More sharing options...
Jeffrey Shaw Posted September 17, 2013 Share Posted September 17, 2013 And look at the car: nifty product placement by Cadillac! Link to comment Share on other sites More sharing options...
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